% Growth of a single roundoff error.
% 
% Try to calculate e by definition
%
% e=\lim_{n\to \infty} (1+1/n)^{n}
%%%%%%%%%%%%%%%%%%%
n=10^10 % problems begin when n begins to approaches 
        % the reciprocal of machine precision (10^-16)
e=(1+1/n)
e=e^n
exp(1)